(9x)^4/3-(10x)^2/3+1=0

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Solution for (9x)^4/3-(10x)^2/3+1=0 equation: 


x in (-oo:+oo)

((9*x)^4)/3-(((10*x)^2)/3)+1 = 0

2187*x^4-100/3*x^2+1 = 0

t_1 = x^2

2187*t_1^2-100/3*t_1^1+1 = 0

2187*t_1^2-100/3*t_1+1 = 0

DELTA = (-100/3)^2-(1*4*2187)

DELTA = -68732/9

DELTA < 0

x belongs to the empty set

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